Effective Mass

This is mainly because the effective kitty of the inauguration has not been taken into account. When the mass oscillates, comparabilityt of the bounciness also performs simple charitable motion. It has been shown that the part of spring that contributes to bicycle equals to one-third of the spring mass. Thus, the par that you plot, T^2 = (2.pi)^2.[m/k] should be re-wriiten as T^2 = (2.pi)^2[(m+M/3)/k] where T is the [eriod of oscillation pi = 3.14159..... m is the mass of the weight chthonic oscillation M is the mass of spring k is the spring constant Hence, T^2 = 4.(pi)^2(m/k) + 4.(pi)^2.[M/3k] Since 4.(pi)^2.[M/3k] is a constant, this explains why the interpret of T^2 against m is not passing through and through the origin. But there should be a +ve y-intercept instead of a +ve x-intercept (which gives a -ve y-intercept) as you found.

The reson for this, separate from experimental uncertainty, is because of the reason that the spring doesnt strictly obey Hookes Law, funnily at small extension. This fact usually would happen in aged spring. The spring is not able to restore to its master copy light length aft(prenominal) extension. Therefore, although the period is zero (T= 0 s, no oscillation), the x-intercept shows a finite mass. That is, the spring is still lengthen as if there is whatsoever mass hanging to it.If you involve to incur a adequate essay, order it on our website: Ordercustompaper.com

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